Cмотри решение во вложении
1)(sinx-3cosx)`=sin`x-(3cosx)`=cosx+3sinx
2)(cos(4x-п/3))`=-sin(4x-п/3)*(4x-п/3)`=-4sin(4x-п/3)
<span>y=|x|(x+1)-6x</span>
x≥0 y=x²-5x
x<0 y=-x²-7x
Sinx+√3cosx=1
1/2sinx+√3/2cosx=1/2
cos(x-П/6)=1/2
x-П/6=+-П/3+2Пk
x1=П/3+П/6+2Пk=П/2+2Пk
x2=-П/3+П/6+2Пk=-П/6+2Пk
0.1 * 10000 + 1 * 100 + 53 =
1000 + 100 + 53 = 1153