У = 9х + 8
Х = 0
у = 8
Ответ ( 0 ; 8 )
D=a3-a2=0.7,
S13= ((2a1+d(n-1))/2)*n, тогда
S13= ((2*(-0.5)+0.7*12)/2)*13= 3.7*13=48.1
Cos2x+8sinx-7=0
cos^2x-sin^2x+8sinx-7=0
1-sin^2x-sin^2x+8sinx-7=0
-2sin^2x+8sinx-6=0
sin^2x-4sinx+3=0
Заменим sinx на a:
a^2-4a+3=0 а€[-1;1]
По теореме Виета решим квадратное уравнение:
а1=1;а2=3-не удовлетворяет условию
При sinx=1: х=arcsin(1)=90
<span>Найдите производную функции
</span>
![y=e^{4x+5}](https://tex.z-dn.net/?f=y%3De%5E%7B4x%2B5%7D)
<span>
Решение
</span>
![y'=(e^{4x+5})' =e^{4x+5}*(4x+5)'=e^{4x+5}*((4x)'+(5)')=](https://tex.z-dn.net/?f=y%27%3D%28e%5E%7B4x%2B5%7D%29%27+%3De%5E%7B4x%2B5%7D%2A%284x%2B5%29%27%3De%5E%7B4x%2B5%7D%2A%28%284x%29%27%2B%285%29%27%29%3D)
![e^{4x+5}*(4+0)=4e^{4x+5}](https://tex.z-dn.net/?f=e%5E%7B4x%2B5%7D%2A%284%2B0%29%3D4e%5E%7B4x%2B5%7D)
Если функция записана как
![y=e^{4x}+5](https://tex.z-dn.net/?f=y%3De%5E%7B4x%7D%2B5)
![y'=(e^{4x}+5)' =e^{4x}*(4x)'+(5)'=4e^{4x}](https://tex.z-dn.net/?f=y%27%3D%28e%5E%7B4x%7D%2B5%29%27+%3De%5E%7B4x%7D%2A%284x%29%27%2B%285%29%27%3D4e%5E%7B4x%7D)