А)12х-3≥-25-10х б)
22х≥-22 - 6х²+х+35≤0 -x²+x+35=0
х≥-1 D= 1+840=841
Ответ. х≥-1 x1=<u>-1+√841</u> =-<u>1+29</u>=-2 1/3
или х∈[-1;+бескон) -12 -12
x2=<u>-1-29</u>= 2 1/2
<u /> -12
Ответ:<span>x∈<span>(<span>−∞;−2<span>13</span></span>]</span>∪<span>[<span>2,5;+∞</span>)
</span></span> или <span><span>x≤−2 <span>1/3</span>;x≥2,5</span></span>
S=integral [-1;1] (1-x^4)dx=(x-x^5/5)[-1;1]=2*(1-1^5/5)=8/5 - это ответ
sin^6X+cos^6X+3sin^2Xcos^2X=(sin^2x+cos^2x)(sin^4x+cos^4x-sin^2xcos^2x)+3sin^2xcos^2x=sin^4x+cos^4x+2sin^2xcos^2x=(sin^2x+cos^2x)^2=1^2=1