<span>х²+3х-10=0⇒Д=9+40=49 х1=2 х2=-5
((x-5)(x+5))² +((x-2)(x+5))²=0</span>
<span />(x-5)²(x+5)²+ (x-2)²(x+5)²=0
(x+5)²((x-5)²+(x-2)²)=0
(x+5)²(x²-10x+25+x²-4x+4)=0
(x+5)²(-14x+29)=0
x+5=0 или -14х+29=0
<span>х=-5 или х=29/14</span>
<span>sin5xcosx-cos5xsinx=0
</span>sin(5x-x)=0
4x=πN
x=πN/4