X-3²=0
x-9=0
x=9
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5x-3<2(x+3)
5x-3<2x+6
5x-2x<6+3
3x<9
x<9/3
x<3
x∈(-бесконечности; 3)
Y = - 3x^2 - 5x - 2
y = 0
- 3x^2 - 5x - 2 = 0
D = 25 - 24 = 1 ; V D = 1
X1 = ( 5 + 1 ) : ( - 6 ) = - 1
X2 = ( 5 - 1 ) : ( - 6 ) = - 2/3
x = 0
y = - 2
Ответ ( 0 ; - 2 ) ; ( - 1 ; 0 ) ; ( - 2/3 ; 0 )