4t+3<0
4t<-3
t<-3/4
ответ: при t∈ (-<span>∞</span> ;-3/4)
1)(1/3*a^2*b)^3*(9ab^2)^2=(1/27*a^6*b^3)(81a^2*b^4)=3a^8*b^7
2)(-5a^3*b)^2*(1/5*a*b^3)^3=(25a^6*b^2)*(1/125*a^3*b^9)=1/5*a^9*b^11
3)(-2/7a*b^4)^2*(-3 1/2a^3*b)^2=(4/49a^2*b^8)(49/4*a^6*b^2)=a^8*b^10
1) 27 . 2) 1/16 . 3) 1/16. 4) 1/64.
√(5x + 6) = 4
5x + 6 = 16
5x = 10
x = 2