Question

X-y=4,xy+y2=6 решите систему уравнений

Answer 1

$\left \{ {{x-y=4} \atop {xy+ y^{2}=6 }} \right. \\ \left \{ {{x=4+y} \atop {(4+y)y+ y^{2} =6}} \right. \\ \left \{ {{x=4+y} \atop {4y+ y^{2}+ y^{2} =6 }} \right. \\ \left \{ {{x=4+y} \atop { y^{2} +4y-6=0}} \right. \\ y^{2} +4y-6=0\\ D=64 \\ y1=-3 \\ y2=1 \\ x-(-3)=4 \\ x=1 \\ x-1=4 \\ x=5 \\ (1;-3),(5;1)$