2х больше -10 , ху больше 45, 3ху больше 135
2х - 3ху больше125
X=10-
![y^{2}](https://tex.z-dn.net/?f=+y%5E%7B2%7D+)
![(10- y^{2} )^{2} -9 y^{2} =0 y^{4} -29 y^{2}+100=0 ](https://tex.z-dn.net/?f=+%2810-+y%5E%7B2%7D+%29%5E%7B2%7D+-9+y%5E%7B2%7D+%3D0%0A%0A+y%5E%7B4%7D+-29+y%5E%7B2%7D%2B100%3D0%0A+)
![y^{2} =t ](https://tex.z-dn.net/?f=+y%5E%7B2%7D+%3Dt%0A)
![t^{2} -29t+100=0 ](https://tex.z-dn.net/?f=+t%5E%7B2%7D+-29t%2B100%3D0%0A)
t1=25 t2=4
![y^{2} =4](https://tex.z-dn.net/?f=+y%5E%7B2%7D+%3D4)
y1=5, y2=-5, y3=2,y4=-2
x1=10-25=-15, x2=6
Ответ:(-15;5) (-15;-5)(6;2) (6;-2)
Вот сама решила не списывала
![(x^3+2*2^x+2)^3\ \textgreater \ (x^3+4^x+2^x)^3\\2(2^x+1)\ \textgreater \ 2^x(2^x+1)\\2^x=t,t\ \textgreater \ 0\\(t+1)(2-t)\ \textgreater \ 0\\-1\ \textless \ t\ \textless \ 2\\-1\ \textless \ 2^x\ \textless \ 2\\2^x\ \textgreater \ -1\\2^x\ \textless \ 2\\x\ \textless \ 1](https://tex.z-dn.net/?f=%28x%5E3%2B2%2A2%5Ex%2B2%29%5E3%5C%20%5Ctextgreater%20%5C%20%28x%5E3%2B4%5Ex%2B2%5Ex%29%5E3%5C%5C2%282%5Ex%2B1%29%5C%20%5Ctextgreater%20%5C%202%5Ex%282%5Ex%2B1%29%5C%5C2%5Ex%3Dt%2Ct%5C%20%5Ctextgreater%20%5C%200%5C%5C%28t%2B1%29%282-t%29%5C%20%5Ctextgreater%20%5C%200%5C%5C-1%5C%20%5Ctextless%20%5C%20t%5C%20%5Ctextless%20%5C%202%5C%5C-1%5C%20%5Ctextless%20%5C%202%5Ex%5C%20%5Ctextless%20%5C%202%5C%5C2%5Ex%5C%20%5Ctextgreater%20%5C%20-1%5C%5C2%5Ex%5C%20%5Ctextless%20%5C%202%5C%5Cx%5C%20%5Ctextless%20%5C%201)
2^x всегда больше любого отрицательного числа значит x∈R
ответ x<1