Нужно найти q: b2/b1= 20/4=5
b3=b1q2= 4×25=100
b4=b1q3= 4×125= 500
1)(1/3*a^2*b)^3*(9ab^2)^2=(1/27*a^6*b^3)(81a^2*b^4)=3a^8*b^7
2)(-5a^3*b)^2*(1/5*a*b^3)^3=(25a^6*b^2)*(1/125*a^3*b^9)=1/5*a^9*b^11
3)(-2/7a*b^4)^2*(-3 1/2a^3*b)^2=(4/49a^2*b^8)(49/4*a^6*b^2)=a^8*b^10
7/b=-3.5b
-3.5b=7/b
b*b=7/(-3.5)
b²=-2
b=²√-2
b1=²√2i
b2=-²√2i