X(x-3)>0
x=0 x=3
x∈(-∞;0) U (3;∞)
1)
3x(x³-4x+6=3x^4-12x²+18x
2)
(x-3)(2x+1)=2x²+x-6x-3=2x²-5x-3
3)
(4a-7b)(5a+6b)=20a²+24ab-35ab-42b²=20a²-11ab-42b²
a)5a²-20ab=5a(a-4b)
b)7x³-14x^5=7x³(1-2x^2)
c)3a-3b+ax-bx=2(a-b)+x(a-b)=(a-b)(3+x)
d)
4x²-12x=0
4x(x-3)=0
X1=0 , x-3=0
X2=3
3х^2 + 4x - 3 = 0
D =16 - 4(-3)(3) = 16 + 36 = 52 YD = 7,2
x1 =( -4 + 7,2) / 6 = 3,2 / 6 = 0,5(3)
x2 = (- 4 - 7,2) /6 = - 11,2 / 6 = - 1, 8(6)
Ответ: х1 = 0,5(3)
х2 = - 1,8(6)