Question

Решите систему уравнений х^2-6х-27<0 х+5/х-4>0

Answer 1

$\left \{ {{ x^{2} -6x-27\ \textless \ 0} \atop { \frac{x+5}{x-4} \ \textgreater \ 0}}<strong>\right.$⇔$\left<strong> \{ {{ (x+3)(x-9)\ \textless \ 0} \atop { \frac{x+5}{x-4} \ \textgreater \ 0}} </strong><strong>\right.$⇔
x∈(-3;9) & x∈(-∞;-5)∪(4;+∞) ⇔x∈(4;9)


Ответ: x∈(4;9)