Log_3 (x - 4) = log_3 (12 - 5x)
x - 4 = 12 - 5x
x + 5x = 12 + 4
6x = 16
x = 16/6
x = 2 (2/3)
смотри во вложении) Думаю правильно)
А). х/(х-2у) + у/(х+2у) + (х²+3ху-2у²)/(4у²-х²)=х(х+2у)+у(х-2у)-х²-3ху+2у²/(х²-4у²)=( х²+2ху+ху-2у²-х²-зху+2у²)/(х²-4у²)=0/(х²-4у²)=0
3ab + a^2 = a*(3b + a)
2cx - 4cx^2 = 2cx*(1 - 2x)
4b^3 - 3b^5 = b^3*(4 - 5b^2)
(x+y)*(5y+x)
(2-x)(a+b)