Число положительное, но находится в интервале до 1
Значит чем больше степень - тем меньше число
Ответ: 1) а
(в+8)^2-4в^2= в^2+16в+64-4в^2= -3в^2+16в+64
A/b=-2
a=-2b
1)2b/a= 2b/(-2b)=-1
2)3a/b = 3*(-2b)=b= -6b/b=-6
3)3*(-2b)+b/-2b-b = -6b+b/-3b=-5b/-3b = 5/3 = 1 2/3
Уравнение наклонной асимптоты: у=kx+b .
![f(x)=\frac{3x^3+2x^2+1}{x^2} \\\\k=\lim\limits _{x \to \infty}\frac{f(x)}{x}=\lim\limits _{x \to \infty}\frac{3x^3+2x^2+1}{x^2\cdot x}=\lim\limits _{n \to \infty}(3+\underbrace {\frac{2}{x}+\frac{1}{x^3}}_{\to 0})=3\\\\b=\lim\limits _{x \to \infty}(f(x)-kx)= \lim\limits _{x \to \infty}(\frac{3x^3+2x^2+1}{x^2}-3x)=\lim\limits _{x \to \infty}\frac{3x^3+2x^2+1-3x^3}{x^2}=\\\\=\lim\limits _{x\to \infty}\frac{2x^2+1}{x^2}=\lim\limits _{x \to \infty}(2+\frac{1}{x^2})=2\\\\\boxed {y=3x+2}](https://tex.z-dn.net/?f=f%28x%29%3D%5Cfrac%7B3x%5E3%2B2x%5E2%2B1%7D%7Bx%5E2%7D+%5C%5C%5C%5Ck%3D%5Clim%5Climits+_%7Bx+%5Cto+%5Cinfty%7D%5Cfrac%7Bf%28x%29%7D%7Bx%7D%3D%5Clim%5Climits+_%7Bx+%5Cto+%5Cinfty%7D%5Cfrac%7B3x%5E3%2B2x%5E2%2B1%7D%7Bx%5E2%5Ccdot+x%7D%3D%5Clim%5Climits+_%7Bn+%5Cto+%5Cinfty%7D%283%2B%5Cunderbrace+%7B%5Cfrac%7B2%7D%7Bx%7D%2B%5Cfrac%7B1%7D%7Bx%5E3%7D%7D_%7B%5Cto+0%7D%29%3D3%5C%5C%5C%5Cb%3D%5Clim%5Climits+_%7Bx+%5Cto+%5Cinfty%7D%28f%28x%29-kx%29%3D+%5Clim%5Climits+_%7Bx+%5Cto+%5Cinfty%7D%28%5Cfrac%7B3x%5E3%2B2x%5E2%2B1%7D%7Bx%5E2%7D-3x%29%3D%5Clim%5Climits+_%7Bx+%5Cto+%5Cinfty%7D%5Cfrac%7B3x%5E3%2B2x%5E2%2B1-3x%5E3%7D%7Bx%5E2%7D%3D%5C%5C%5C%5C%3D%5Clim%5Climits+_%7Bx%5Cto+%5Cinfty%7D%5Cfrac%7B2x%5E2%2B1%7D%7Bx%5E2%7D%3D%5Clim%5Climits+_%7Bx+%5Cto+%5Cinfty%7D%282%2B%5Cfrac%7B1%7D%7Bx%5E2%7D%29%3D2%5C%5C%5C%5C%5Cboxed+%7By%3D3x%2B2%7D)