Question

Помогите решить, если можно подробно

Answer 1

1.
 1)   =sin[2π+(π/2-α)]= sin(π/2 - α) = cosα
 2)   = cos(43π/2 -α) = cos[2π·11 -π/2 -α] = cos[-{π/2+α] = cos(π/2 +α) = -sinα
 3)  =tg(2π·3 +π/2+α) = tg(π/2+α) = -ctgα
 4)  = -ctg[(2π·2 -π/2)-α] = ctg[-(π/2 +a] = -ctg(π/2+a) = -(-tga)= tga
 5)  = - tg(6π +π -a) = -tg(π-a) = -(-tga) = tga
 6)  = -tg(360+270 -a) = -tg(180+(90 -a)) =-tg(90-a)=-ctga

2.
    1)  = -tga
    2)  = -cosa
    3)  = cos(3·360+90+a)= cos(90+a) = -sina
    4)  = tg(360+180 -a) = tg(180-a) = -tga
    5)  = sin(2·360+180+a) = s-n(180+a) = -sina
    6(  =  -tg(630 -a) = -tg(720 - 90 -a) = -tg[-(90+a)] = tg(90+a) = -ctga

3.
    sin911 = sin(3·360 - 169) = -sin(180-11) = -(sin11) = -sin11
    sin911 = sin(720+191)= sin(180+11) = -sin11
    
    cos326 = cos(320+6) = cos6
    3)   = -tg639 = -tg(720 -81)= - tg( -81) = -(-tg81) = tg81
    4)  = -ctg700= - ctg(720-20) = -ctg( -20) = -(-ctg20) = ctg20
     5) = -sin3206= -sin(10·360 +6) = -sin6