Cos(π+2α)+sin(π+2α)*tg(π/2+α)=-cos2α-sin2α*(-ctgα)=
=-(cos²α-sin²α)+2sinαcosα*cosα/sinα=-cos²α+sin²α+2cos²α=cos²α+sin²α=1.
-4x(в квадрате)это 16x+3x+7=19x+7
x²(x-1)²+x(x²-1)=2(x+1)²
x²(x²-2x+1)+x(x²-1)=2(x²+2x+1)
x⁴-2x³+x²+x³-x=2x²+4x+2
x⁴-x³-x²-5x-2=0
x⁴+x³-2x³-x²-2x²+2x²-x-4x-2=0
x²(x²-2x-1)+x(x²-2x-1)+2(x²-2x-1)=0
(x²+x+2)(x²-2x-1)=0
x²+x+2=0
D<0, нет корней
x²-2x-1=0
D= 4+4=8
x1= (2+√8)/2= (2+2√2)/2= 1+√2
x2= (2-2√2)/2= 1-√2