1)(x+6)(x-6)>0
x=-6 u x=6
<u>------</u> -6 ----- 6 <u>-----</u>>x
xE(-беск;-6)U(6;беск)
2)(x-1/3)(x-1/5)<=0
x=1/3 u x=1/5
----- <u>1/5 ----- 1/3</u> ---->x
xE[1/5;1/3]
3)(x+0,1)(x+6,3)>=0
x=-0,1 u x=-6,3
<u>---- -6,3</u> ---- <u>-0,1 ----</u>>x
xE(-беск;-6,3]U[-0,1;беск)
2(√3+1)/[(√3-1)(√3+1)]=2(√3+1)/(3-1)=2(√3+1)/2=√3+1
7a(a-b)-3(b-a)²=7a(a-b)-3(b²-2ab+a²)=
=7a²-7ab-3b²+6ab-3a²=4a²+ab-3b²
<span>а) 4p</span>²<span>-( x + y)</span>²=4p²-x²-2xy-y²<span>
б) a</span>²<span>-( b+c) =a</span>²-b-c<span>
в) x-y+x</span>²<span>-2xy+y</span>²=(x-y)+(x-y)²=(x-y)(1+x-y)<span>
г) k</span>²<span>+2mk+m</span>²<span>-k-m=(k+m)</span>²-(k+m)=(k+m)(k+m-1)
Например: 24/30= они оба делятся на 6.будет 4/5