Question

Срочно !!!!!!!!!!!!!!!!!!!!!!!!!!!​

Answer 1

Ответ:  $\displaystyle x=-2\frac{5}{9}.$

Решение:

$\displaystyle \frac{2}{\sqrt{x+3} } = 3 \;\;\;\;\; {\tt ODZ:\;x+3>0; \; x>-3}\\\\\sqrt{x+3} = \frac{2}{3}\\\\(\sqrt{x+3})^2=\bigg(\frac{2}{3}\bigg)^2\\\\x+3=\frac{4}{9} \\\\x=\frac{4}{9} -3\\\\x=-\frac{23}{9} =-2\frac{5}{9} > -3.$