Question

Logx по основанию 8 = -1/3

Answer 1

Добавлю ответ
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Answer 2

ОДЗ
x > 0

log_8 (x) = - 1/3
8^(-1/3) = x
(2^3)^(-1/3) = x
2^(-3/3) = x
x = 2^(-1)
x = 1/2
x = 0,5