![1)k=-\frac{5}{6}](https://tex.z-dn.net/?f=1%29k%3D-%5Cfrac%7B5%7D%7B6%7D)
Степень одночлена равна : 2 + 6 + 3 = 11
2) P = 3xy² + 2xy² + 7x -2y + 2xy² +3x - y = 7xy² + 10x - 3y
![3)(\frac{1}{3}) ^{-1}-( \frac{6}{7}) ^{0} +(\frac{1}{2}) ^{2}:2=3-1+ \frac{1}{4}:2=2+ \frac{1}{8}=2 \frac{1}{8}=2,125](https://tex.z-dn.net/?f=3%29%28%5Cfrac%7B1%7D%7B3%7D%29+%5E%7B-1%7D-%28+%5Cfrac%7B6%7D%7B7%7D%29+%5E%7B0%7D+%2B%28%5Cfrac%7B1%7D%7B2%7D%29+%5E%7B2%7D%3A2%3D3-1%2B+%5Cfrac%7B1%7D%7B4%7D%3A2%3D2%2B+%5Cfrac%7B1%7D%7B8%7D%3D2+%5Cfrac%7B1%7D%7B8%7D%3D2%2C125)
4)(8,47n⁵m⁴ + 77n⁴m³) : (7,7n⁴m³) - 10=77n⁴m³(0,11nm + 1) : (7,7n⁴m³) - 10=
= 10(0,11nm + 1) - 10 = 1,1nm + 10 - 10 = 1,1nm
![5)\frac{(a^{4})^{3}*(b^{10})^{2}}{a^{8}*(b^{5})^{3}}= \frac{a^{12}*b^{20}}{a^{8}*b^{15}}= a^{12-8}* b^{20-15}= a^{4}* b^{5} \\1^{4}*( -1)^{5}=1*(-1)=-1](https://tex.z-dn.net/?f=5%29%5Cfrac%7B%28a%5E%7B4%7D%29%5E%7B3%7D%2A%28b%5E%7B10%7D%29%5E%7B2%7D%7D%7Ba%5E%7B8%7D%2A%28b%5E%7B5%7D%29%5E%7B3%7D%7D%3D+%5Cfrac%7Ba%5E%7B12%7D%2Ab%5E%7B20%7D%7D%7Ba%5E%7B8%7D%2Ab%5E%7B15%7D%7D%3D+a%5E%7B12-8%7D%2A+b%5E%7B20-15%7D%3D+a%5E%7B4%7D%2A+b%5E%7B5%7D+%5C%5C1%5E%7B4%7D%2A%28+-1%29%5E%7B5%7D%3D1%2A%28-1%29%3D-1)
6) (9st - 1,6)(10 + 1,8st) = 90st + 16,2s²t² - 16 - 2,88st = 16,2s²t² + 87,12st - 16
Ответ:
-40.
Объяснение:
-13 1/3*1 7/23-13 1/3*1 16/23 = -13 1\3(1 7\23+1 16\23)=-13 1\3 * 3 = -40\3 * 3 = -40.
Буду писать сразу ответ без примера
1) a²-2ab-(9b²+6ab+a²)=a²-2ab-9b²-6ab-a²=-8ab-9b²
2) m²+16m+64-(m²-4n²)=m²+16m+64-m²+4n²=16m+64+4n²
3) 3(b²-20b+100)+8b-5b²=3b²-60b+300+8b-5b²=-2b²-52b+300
4) n²+30n+225-n²+19n=49n+225
5) 36b²-12c-(36c²+12c+1)=36c²-12c-36c²-12c-1=-24c-1
6) (6-5m)×(6+5m)+25m²-40m+16=36-25m²+25m²-40m+16=52-40m
А) -х^3= -216
б) 2х^3=1728
в) -2x^3= -1728
Решение задания приложено