Решение
lg 9/ lg3 = lg3² / lg3 = 2* lg3 / lg3 = 2
4*(x-5)-(7*x+9)=4x-20-7x-9= -3x-29
а) 5х+3у-2х-9у = 3x - 6y
б) 2(3а-4)+5 =6a - 8 + 5 = 6a - 3
в) 15а-(а-3)+(2а-1)= 15a - a+3+2a-1 = 16a + 2
2. sin²γ+sinγ·cosγ·ctgγ=sin²γ+sinγ·cosγ·cosγ/sinγ=sin²γ+cos²γ=1;
3. (sinx-sin³x)/cos²x+2sinx=sinx(1-sin²x)/cos²x+2sinx=
=sinx·cos²x/cos²x +2sinx=sinx+2sinx=3sinx;
4. (5sinφ-3)/(4-5cosφ)-(4+5cosφ)/(3+5sinφ)=
=[(25sin²φ-9)-(16-25cos²φ)]/(4-5cosφ)(3+5sinφ)=
=(25sin²φ-25+25cos²φ)/(4-5cosφ)(3+5sinφ)=
=(25(sin²φ+cos²φ-1)/(4-5cosφ)(3+5sinφ)=0/(4-5cosφ)(3+5sinφ)=0