Решение
<span>Найти производную
1) у=sin3х -cos3х и вычислить ее значение, если х=3П/4;
y` = 3cos3x + 3sin3x
</span><span>если х=3П/4
</span>y`(3π/4) = 3cos(3*3π/4) + 3sin(3*3π/4) = 3cos(2π + π/4) + 3sin(2π + π/4) =
= 3cosπ/4 + 3sinπ/4 = 3√2/2 + 3√2/2 = 6√2/2 = 3<span>
2) у=</span>√(<span>25-9х), если х=1
y` = - 9 / [2</span>√(25 - 9x)
y`(1) = - 9 / [2<span>√(25 - 9*1) = - 9 / (2</span>√16) = - 9 / 8 = - 1(1/8)<span>
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