Question

Сократить дробь √x+1/x-1

Answer 1

$( \sqrt{a} ) ^{2} =a, a \geq 0$
$\frac{ \sqrt{x} +1}{x-1} = \frac{ \sqrt{x} +1}{( \sqrt{x} ) ^{2} - 1^{2} } = \frac{ \sqrt{x} +1}{( \sqrt{x} +1)*( \sqrt{x} -1)} = \frac{1}{ \sqrt{x} -1}$