Question

Преобразуйте выражение в многочлен: (6m+7)^2=(4z+5/8)^2=(3/5-3x)^2=(-7a+3b)^2=(0,9b-5c)^2=(2/3x-3/2y)^2=

Answer 1

(6m+7)^2=36m^2+84m+49=120m+49 (3/5-3x)^2=0,36-1,08x+9x^2 (-7a+3b)^2=49a^2-42ab+9b^2 (0,9b-5c)^2=0,81b^2-9bc+25c^2

Answer 2

$(6m+7)^{2}=36m^{2}+84m+49$
$(4z+ \frac{5}{8})^{2}=16z^{2}+5z+ \frac{25}{64}$
$( \frac{3}{5}-3x)^{2}= \frac{9}{25}- \frac{18}{5}x+9 x^{2}$
$(-7a+3b)^{2}=49a^{2}-42ab+9b^{2}$
$(0.9b-5c)^{2}=0.81b^{2}-9bc+25c^{2}$
$( \frac{2}{3}x- \frac{3}{2}y)^{2}= \frac{4}{9}x^{2} -2xy+ \frac{9}{4}y^{2}$