y"=2" *(x^2-2x+1)+2(x^2-2x+1)"=0+4x-4. 4x-4=0, x=1(наим)
Log ( 1/2 ) ( 3x - 5 ) = 2
1/2 ^ 2 = 3x - 5
0,25 = 3x - 5
3x = 5,25
X = 1,75
Решение:
8x^4-16x^3y=8x^3*(x-2y)
(4х² - 2х + 3 ) + ( - 2х² + 3х ) =
= (4х² - 2х²) + ( - 2х + 3х) + 3 =
= 2х² + х + 3