Question

Lim(x-> 0)sin ^2 5x/(cos(4x)* tg(x)) =

Answer 1

$\lim_{x \to 0} \frac{\sin^25x}{\cos4x \cdot tgx} = \lim_{x \to 0} \frac{25x^2}{x\cdot \cos4x} = \lim_{x \to 0} \frac{25x}{\cos 4x} =0$