2^x^2=0,25*2^8x+22 2^x^2=2^(-2)*2^8x+22 2^x^2=2^8x+20 x^2=<span>8x+20
</span>x^2-<span>8x-20=0 x1+x2=8 x1x2=20 x1=10 x2=-2</span>
Bn=162 * (1/3)^n
S₄ - ?
B₁=162* (1/3)=54
B₂=162*(1/3)²=162*(1/9)=18
B₃=162*(1/3)³=162*(1/27)=6
B₄=162*(1/3)⁴=162*(1/81)=2
S₄=54+18+6+2=80
Ответ: 80
6.793х + 0.007х +1\5х = 7042
(6.793+ 0.007+ 1\5)х = 7042
(6.8+0.2)х = 7042
7х =7042
х = 7042 / 7
х = 1006
12а+а-4+3 вот держи ответ
<span>cos25°×cos65°=?
есть формула: 2Cos</span>αCosβ = Cos(α+β) + Cos(α-β). применим её.
Cos25°Cos65° = 1/2*2Cos25°Cos65° = 1/2*(Cos90° + Cos40°) = 1/2Cos40°
(учли, что Cos90° = 0)