Question

3у(в квадрате)-2у-8=0

Answer 1

$3y^2-2y-8=0,\\D=(-2)^2-4\bullet3\bullet(-8)=4+96=100,\\\\y_1=\frac{-(-2)+\sqrt{100}}{2\bullet3}=\frac{12}{6}=2,\\y_2=\frac{2-\sqrt{100}}{6}=-\frac{8}{6}=-1\frac{1}{3}.$

Ответ: <u />$y_1=2,\ y_2=-1\frac{1}{3}.$