Question

Найдите производную функции y= 4x^3-3x+ 1/^3√x2

Answer 1

$(4x^3-3x+x^{-\frac{2}{3}})'=(4x^3)'-(3x)'+(x^{-\frac{2}{3}})'=12x^2-\frac{2}{3}x^{-\frac{5}{3}}-3$

Answer 2

Y=4x^3-3x+x^(-2/3)            y`(x^n)=nx^(n-1)
y`=(4x^3-3+x^(-2/3))`=4*3x^(3-1)-3+(-2/3)*x^(-2/3-1)=12x^2-2x^(-5/3)/3-3