Question

Помогите пожалуйста...

Answer 1

$\sqrt[3]{2^{x}\sqrt[3]{4^{x} *0,125^{\frac{1}{x}}}}=\sqrt[9]{4}\\\\2^{x}\sqrt[3]{2^{2x}*(2^{-3})^{\frac{1}{x}}}=2^{\frac{2}{3} }\\\\2^{x}\sqrt[3]{2^{\frac{2x^{2}-3 }{x} } }=2^{\frac{2}{3} }\\\\2^{x }*2^{\frac{2x^{2} -3}{3x} }=2^{\frac{2}{3} } \\\\2^{\frac{5x^{2}-3 }{3x} }=2^{\frac{2}{3} }\\\\\frac{5x^{2}-3 }{3x}=\frac{2}{3} \\\\5x^{2}-2x-3=0\\\\D=(-2)^{2}-4*5*(-3)=4+60=64=8^{2}\\\\x_{1} =\frac{2+8}{10}=1\\\\x_{2}=\frac{2-8}{10}=-0,6\\\\x_{1}+x_{2}=1-0,6=0,4$