<span>9x²-60x+100=0
(3х-10)</span>² = 0
(3х-10)·(3х-10) = 0
3х-10=0
3х = 10
х = 10 : 3
х = 3 ¹/₃
По теореме Виета
сумма корней = -a
произведение корней = b
b=(1/m-5)(1/n-5)
a=-((1/m)-5+(1/n)-5)
a+b=(1/m-5)(1/n-5)-(1/m-5+1/n-5)
2x - 1 <= 5x + 1
2x - 5x<= 1+ 1
- 3x <= 2
x >= - 2/3
x э [ - 2/3; + бесконечности)