Question

81^ log3 5 +27^log9 36 + 3^4log 9 7

Answer 1

$81^{log_{3}5}+ 27^{log_{9}36}+ 3^{4log_{9}7}=( 3^{log_{3}5}) ^{4}+( 3^{log_{3}6}) ^{3}+( 3^{log_{3}\sqrt{7}}) ^{4}= 5^{4}+ 6^{3}+( \sqrt{7}) ^{4}=625+216+49=890$

Answer 2

81^ log3 5 +27^log9 36 + 3^4log 9 7=

3^ 4log3 5 +3^3log3 √36 +

+ 3^4log3 √ 7 =

3^ log3 5^4 +3^log3 6^3+ 3^log3 7^2=

= 5^4+ 6^3 +7^2 = 890