Question

Решите уравнение а) x(x-3)-(12-6x+ )=6 б)  - = 1

Answer 1

$x(x-3)-(12-6x+x^2)=6\\ x^2-3x-12+6x-x^2=6\\ 3x=18\\ x=6$
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$\frac{x+3}{2} - \frac{x-4}{7} =1\\\\ \frac{7*(x+3)}{7*2} - \frac{2*(x-4)}{2*7} -\frac{1*2*7}{2*7}=0\\\\ \frac{7*(x+3)-2*(x-4)-1*2*7}{7*2} =0\\\\ 7*(x+3)-2*(x-4)-1*2*7=0\\ 7x+21-2x+8-14=0\\ 5x+15=0\\ 5x=-15\\ x=-3$