Question

Решите уравнение:4 x^{2} − 19x+32= − 6 x^{2} − 6x+41

Answer 1

4x^2 - 19x + 32 = - 6x^2 - 6х + 41
4х^2 + 6х^2 - 19х + 6х + 32 - 41 = 0
10х^2 - 13х - 9 = 0
D = 169 + 360 = 529 = 23^2
X1 = ( 13 + 23 ) : 20 = 1,8
X2 = ( 13 - 23 ) : 20 = - 0,5

Answer 2

4x²-19x+32=-6x²-6x+41
10x²-13x-9=0
D=b²-4ac=169+360=529
$\sqrt{D}=23 \\ \\ x_{1}= \frac{13-23}{20}=-0,5 \\ \\ x_{2}=\frac{13+23}{20}= \frac{36}{20}=\frac{9}{5}=1,8$
Ответ:-0,5;1,8.