1)f(x)=sin x, f´(x) = cos x,cos(-pí/4) = cos(pí/4) = V2/2
2)y=x-2, y´= 1, v=1
3)g(x) = 1/x, g´(x) = -1/xˇ2,g´(2.V3) = -1/(4.3)=-1/12, k=tg alfa = -1/12
Х-стоимость ручки
0,8х-стоимость тетради
1,6х-стоимость 2 тетрадей
х-100%
(1,6х-х)-?%
0,6х*100/х=60%
6=2-b+3
b=5-6=-1
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![ax^2+bx+c=0\\ ](https://tex.z-dn.net/?f=ax%5E2%2Bbx%2Bc%3D0%5C%5C%0A)
Пусть -
![a = 2^{a_1}\\ b = 2^{a_2}\\ c = 2^{a_3}\\ a_1,a_2,a_3 \in N\\ ](https://tex.z-dn.net/?f=a+%3D+2%5E%7Ba_1%7D%5C%5C%0Ab+%3D+2%5E%7Ba_2%7D%5C%5C%0Ac+%3D+2%5E%7Ba_3%7D%5C%5C%0Aa_1%2Ca_2%2Ca_3+%5Cin+N%5C%5C%0A)
Квадратное уравнение имеет два различных действительных корня при дискриминанте большим нуля:
![D = b^2-4ac\\ b^2-4ac \ \textgreater \ 0\\ 2^{2a_2} - 2^2*2^{a_1}*2^{a_3} \ \textgreater \ 0\\ 2^{2a_2} - 2^{a_1+a_3+2} \ \textgreater \ 0\\ 2^{2a_2} \ \textgreater \ 2^{a_1+a_3+2} \\ 2a_2\ \textgreater \ a_1+a_3+2\\ a_2 \ \textgreater \ \frac{a_1+a_3}{2}+1\\](https://tex.z-dn.net/?f=D+%3D+b%5E2-4ac%5C%5C%0Ab%5E2-4ac+%5C+%5Ctextgreater+%5C++0%5C%5C%0A2%5E%7B2a_2%7D+-+2%5E2%2A2%5E%7Ba_1%7D%2A2%5E%7Ba_3%7D+%5C+%5Ctextgreater+%5C++0%5C%5C%0A2%5E%7B2a_2%7D+-+2%5E%7Ba_1%2Ba_3%2B2%7D+%5C+%5Ctextgreater+%5C++0%5C%5C%0A2%5E%7B2a_2%7D+%5C+%5Ctextgreater+%5C++2%5E%7Ba_1%2Ba_3%2B2%7D+%5C%5C%0A2a_2%5C+%5Ctextgreater+%5C+a_1%2Ba_3%2B2%5C%5C%0Aa_2+%5C+%5Ctextgreater+%5C++%5Cfrac%7Ba_1%2Ba_3%7D%7B2%7D%2B1%5C%5C)
При
![a_2=max(k,m,n)](https://tex.z-dn.net/?f=a_2%3Dmax%28k%2Cm%2Cn%29)
это равенство будет выполняться всегда