Question

ПОМОГИТЕ РЕШИТЬ 2 ПРИМЕРА ДАМ 50 БАЛЛОВ

Answer 1

$\frac{ \sqrt[3]{250} }{ \sqrt[3]{54} } = \sqrt[3]{ \frac{250}{54} }= \sqrt[3]{ \frac{125\cdot2}{27\cdot2} } = \frac{5}{3} =1\frac{2}{3}$

$2)....= \sqrt[3]{7^2-( \sqrt{22} )^2} = \sqrt[3]{49-22}= \sqrt[3]{27} =3$

Answer 2

=(250/54)¹/³=(125/27)¹/³=((5/3)³)¹/³=5/3= 1 целая 2/3

2.   =((7-√22)(7+√22))¹/³=(7²-(√22)²)¹/³=(49-22)¹/³=27¹/³=(3³)¹/³=3