Question

M2-9/2m2+1*(6m+1/m-3+6m-1/m+3) срочно решить нодо

Answer 1

$\frac{m^2-9}{2m^2+1}*(\frac{6m+1}{m-3}+\frac{6m-1}{m+3})=\frac{m^2-9}{2m^2+1}*(\frac{(6m+1)(m+3)}{m^2-9}+\frac{(6m-1)(m-3)}{m^2-9})=\frac{m^2-9}{2m^2+1}*\frac{6m^2+19m+3+6m^2-19m+3}{m^2-9}=*\frac{6(2m^2+1)}{2m^2+1}=6$