<span>task/28177870
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Найти производную функции
1 . y=(x+9)</span>⁴<span>/ (x-3) 2. y=x*sin(3x-π/2)
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</span>1.
* * * ( u / v) ' =( u ' *v - u *v ' ) / v² * * *
y ' = ((x+9)⁴/ (x-3) ) ' = (4(x+9)³ (x-3) - (x+9)⁴ *1) / (x-3)² .
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2.
* * * (uv) ' = u ' *v + u*v ' ; sin(3x-π/2)= - sin(π/2 - 3x) = - cos3x * * *
y ' ( x*sin(3x-π/2)' = (- x* cos3x ) ' = - ( x* cos3x ) ' =
- ( 1*cos3x +x*(-sin3x)*(3x) ' ) = 3sin3x - cos3x .
(x-2)(x+2)=0
x=2 или х=-2
ответ: (-∞ ; 2] U [-2; +∞)
остальное думаю сами сможете сделать))
5a(a+b+c)-5b(a-b-c)-5c(a+b-c)= 5a^2+5ab+5ac-5ab+5b^2+5bc-5ac-5bc+5c^2= 5a^2+5b^2+5c^2
<span>10 (х-7)《9 (х-5)-24
10х-70 </span>《9х-45-24
10х-9х 《 -45-24+70
х 《1
Y=2x²
1)y=200
200=2x², x²=100, /10,200/,/-10,200/
2)y=800
800=2x²,x²=400, /20,800/,/-20,800/
3)y=50x
50x=2x²,2x²-50x=0, x²-25x=0, x(x-25)=0, /0,0/, /25,1250/
4)y=-3200x
-3200x=2x², x²+1600x=0,x(x+1600)=0, /0,0/, /-1600,5120000/