Решение:<span><span>4−7⋅5x=</span><span>4−7⋅5x=</span></span><span><span>=4−35x=</span><span>4−35x=</span></span><span><span>−35x+4</span><span>−35x+4</span></span>Ответ: <span>−35x+<span>4
Другое надо подумать
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1) 5z(z^2-1)=0
5z=0, z=0
z^2-1=0, (z-1)(z+1)=0, z=1, z= - 1
2) z(1-9z^2)=0
z=0
1-9z^2= 0, (1-3z)(1+3z)= 0, z=1/3, z= - 1/3
f(2006)=f(2003*2+0)=f(0)=1
f(2007)=f(2003*2+1)=f(1)=0
<span>f(2006)*f(2007)+2*f(0)=1*0+2*1=2</span>
A-b=0
a=b
3b+b=40
4b=40
b=10
b=a=10