Sinx-1=cosx(sinx-1)
sinx-1-cosx(sinx-1)=0
(sinx-1)(1-cosx)=0
1. sinx-1=0
sinx=1
x = π/2 + 2πk
2. 1-cosx=0
cosx=1
x = 2πk
Ответ: π/2 + 2πk; 2πk; k€Z
(2x + 3)² - (x - 1)²=4х² + 12х + 9 - (х² - 2х +1) = 4х² + 12х +9 - х² +2х - 1 = 3х² +14х +8
Tg^2 x-th x+ 1=0
t^2-t+1=0
D=1 ^ 2-4*1=-3
25а^4b^4
....................