Question

Решите уравнение |cosx|=sinx

Answer 1

|cosx|≥0 => |cosx|=cosx
cosx=sinx
1=tgx

$x= \frac{ \pi }{4} +2 \pi k$


|cosx|<0 => |cosx|=-cosx
-cosx=sinx
-1=tgx

$x= \frac{3 \pi }{4} +2 \pi k$