А) 3х+1=0
3х=-1
х=-1/3 (2)
Б) -x+2=0
x=2 (3)
В) x-5=0
x=5 (4)
<span><span><span>√33-8x=x </span></span></span>
3x²+40x+10<-x²+11x+3
3x²+40x+10+x²-11x-3<0
4x²+29x+7<0
4x²+29x+7=0
D=841-112=729=27²
x1=(-29+27)/8=-0,25
x2=(-29-27)/8=-7
Ответ: х∈(-7;-0,25)
(sin(270-36)+cos(180+36))/(sin(180-36)-cos(90+36)) *tg36=
=(-cos36-cos36)/(sin36+sin36 *tg36=-2cos36/2sin36 *tg36=ctg36*tg36=1
![\frac{log_9(\sqrt{22})}{log_9(22)}\\\\ log_{22}(\sqrt{22})\\\\ log_{22}(22^{\frac{1}{2}}) = \frac{1}{2}](https://tex.z-dn.net/?f=%5Cfrac%7Blog_9%28%5Csqrt%7B22%7D%29%7D%7Blog_9%2822%29%7D%5C%5C%5C%5C%20log_%7B22%7D%28%5Csqrt%7B22%7D%29%5C%5C%5C%5C%20log_%7B22%7D%2822%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%29%20%3D%20%5Cfrac%7B1%7D%7B2%7D)
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