<span>х(х+y)²-y(x-y)²+2y(x²+y²)</span>=x(x²+2xy+y²)-y(x²-2xy+y²)+2x²y+2y³=
=x³+2x²y+xy²-x²y+2xy²-y³+2x²y+2y³=x³+3x²y+3xy²+y³=(x+y)³
(x+y)³ при <span>х=2,5 , у=0,5
(2,5+0,5)³=3³=27</span>
(y^2-ay+cy-ac)/(y^2-ay-cy+ac)=(y*(y-a)+c(y-a))/(y*(y-c)-a(y-c))=
=((y-a)*(y+c))/((y-c)*(y-a))=(y+c)/(y-c)
(y^2-2cy+c^2)/(y^2-2ay+a^2)=((y-c))^2)/((y-a)^2)
умножаем первое на второе и получим:
((y+c)*(y-c)^2)/((y-a)^2*(y-c))=((y+c)*(y-c))/((y-a)^2)=(y^2-c^2)/(y^2-2ay+a^2)
X^2 = A ; A > 0
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9A^2 - 82A + 9 = 0
D = 6724 - 324 = 6400 ; √ D = 80
A1 = ( 82 + 80 ) : 18 = 9
A2 = ( 82 - 80 ) : 18 = 2/18 = 1/9
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X^2 = 9
X1 = 3
X2 = - 3
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X^2 = 1/9
X3 = 1/3
X4 = - 1/3
Ответ:
Объяснение:
√18(x-2)^5=√2×3²×((x-2)²)²×(x-2)=3×(x-2)²√2×(x-2);