Question

найдите производные функции: 1. y=\frac{4x+1}{3-2x} 2. y=(3-4x^{2})^{3} 3. y=3sin(3x-\frac{\pi}{3}

Answer 1

1. y=(4x+1)/(3-2x)

y'=[4(3-2x)-(-2)*(4x+1)]/(3-2x)²=24/(3-2x)²

2. y=(3-4x²)³

y'=3(3-4x²)²*(3-4x²)'=-24x*(3-4x²)²

3. y=3sin(3x-π/3)

y'=3cos(3x-π/3)*(3x-π/3)'=9cos(3x-π/3)