Question

Немало баллов за простое уравнение) (1/7)^7+х = 49

Answer 1

$(\frac{1}{7})^{7+x}=49\\\\(\frac{1}{7})^{7+x}=7^{2}\\\\(\frac{1}{7})^{7+x}=(\frac{1}{7}^{-2} \\\\7+x=-2\\\\x=-9$