(1+ y)*(y+1)=1
(1+y)²=1
1+2y+y²=1
1+2y+y²-1=0
y²+2y=0
y(y+2)=0
<u>y₁=0 </u>
y+2=0
<u>y₂= -2</u>
ОТВЕТ: <u>y₁=0 </u>, <u> y₂= -2</u>
8(3x+y)^2-12x(6x+4y)=8(9x^2+6ху+y^2)-72x^2-48хy=72x^2+48ху+8y^2-72x^2-48хy=8y^2
15*4 x 45*3 / 5*6 x 3*9=15*4 x 3*6 x 5*3 / 5*6 x 3*9=15*4 / 3*3 x 5*3=15*4/15*3=15
45*3=9*3 x 5*3=3*6 x 5*3