Question

1,2, пожалуйста.,..,.,.,..,

Answer 1

1.$AB = \sqrt{16+16} = \sqrt{32}$.

$AB=DB=\frac{\sqrt{32} }{2} =\frac{\sqrt{32} }{\sqrt{4}}=\sqrt{\frac{32}{4} } =\sqrt{8}$.

$CD=\sqrt{16-8} =\sqrt{8}$.

$MC=\sqrt{9-8} =\sqrt{1} =1$.

2.$AD=DB=\frac{1}{2} AB=\frac{2\sqrt{3} }{2} =\sqrt{3} .$

$DC=\sqrt{12-3} =\sqrt{9} =3.$

$MC=\sqrt{16+9} =\sqrt{25} =5.$