6x^2 + x = 7
( x-1 ) ( 6x+7 ) = 0
6 ( x + 1 / 12 )^2 - 169 / 24 = 0
х = - 7 / 6
х = 1
Если х = 0, то у=2
если х = 1, то у=1
через точки (0; 2), и (1;1) нужно построить прямую
X(y+z)-(2y+2z)=x(y+z)-2(y+z)=(y+z)(x-2)
a(b-c)-(4b-4c)=a(b-c)-4(b-c)=(b-c)(a-4)
x(y-z)-(y-z)=(y-z)(x-1)
5(c-b)+(ab-ac)=5(c-b)-(-ab+ac)=5(c-b)-a(c-b)=(c-b)(5-a)
(3/(2(m+3))-(m-2)/(m+3)^2=
(3(m+3)-2(m-2))/(2(m+3)^2=
(3m+9-2m+4)/2(m+3)^2=
(m+13)/2(m+3)^2