B3=8;b5=32
b1*q²=8
b1*q⁴=32
q²=4
q=±2
b1=8/q²=8/4=2
2;4;8;16;32;64;128;256
s(8)=b1(qⁿ-1)/(q-1)=
2(2^8-1)/(2-1)=2*255=510
X(x+2)-3 = 4 (x+1)-1
x^2+ 2x - 3 = 4x + 4 - 1
x^2 + 2x - 4x = 3 + 4 -1
x^2 - 2x = 6
x^2 - 2x - 6 = 0
x1+x2 = 2
x1 * X2 = -6
X1 = -3
X2 = 2
не помню, вроди так
Решение во вложении--------------------
X^2+(x+1)^2=(x+2)^2
2x^2+2x+1=(x+2)^2
2x^2+2x+1x^2+4x+4
x^2-2x-3=0
(x-3)(x+1)=0
x-3=0 x+1=0
x=3 x+1=0
x=3 x=-1