<span>1) (7-х)(7+х)+(х+3)</span>² = 7² - х² + (х² + 2·х·3 + 9) = 49 - х² + х² + 6х + 9 =
= 58 + 6х = 2·(29 +3х)
<span>
2) (12р</span>⁶<span>q</span>²<span>)/(8p</span>⁴<span>q</span>⁵) = (3p²)/(2q³)<span> </span>
- 5a^6 * x * 3*x *b^4 = -15*a^6 *b^4 *x²
4x^2-x=0
x(4x-1)=0
x1=0
4x-1=0
4x=1
x=0,25
x2=0.25
У=4/х^2=4*х^(-2)
f'(x)=(-2)*4x^(-2-1)=-8x^(-3)=-8/x^3
-8/x^3=0
x^3=0,x=0
[-3;-1;0]
f(-3)=4/x^2>4/(-3)^2=4/9;
f(-1)=4/(-1)^2=4/1=4
f(0)=4/0^2=4/0=0
значит наименьшее f(x)=0,наибольшее f(x)=4
<span> х2+8х+15<0
(x+3)(x+5)<0
=========-5======-3========
++++++++++----------</span>