1) log2(x^2 - 2x) = 3
x^2 - 2x = 2^3
x^2 - 2x - 8 = 0
x1 = -2 x2 = 4
<span>2) log3(x-2)<2
x - 2 < 3^2
x < 11
</span>
2х² = 2-4х+х
2х²= 2-4х²
2х²+4х²=2
6х²=2
х²=0.33333
В первом выражении иксы сокращаются. Ответ:
2а*6а^2+ b/3a = 2*0.5 * 6*0.5^2 + (-3/4) / 3*0.5 = 1 * 6*0.25 + (-3/4)*1.5 =
= 1.5 + (-3/4)*1.5 = 1.5 (1 - 3/4) = 1.5* (1/4) = 1.5*.25=0.375